Array Partition I Problem & Solution

Given an integer array nums of 2n integers, group these integers into n pairs (a1, b1), (a2, b2), ..., (an, bn) such that the sum of min(ai, bi) for all i is maximized. Return the maximized sum.

See the array partition i problem on LeetCode.

C++ Solution

The runtime complexity of this algorithm is O ( n log n ) O(n\log{}n) .

#pragma GCC optimize("Ofast")
#pragma GCC optimization("unroll-loops")

static const int _=[](){ios::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);return 0;}();

class Solution {
public:
  int arrayPairSum(vector<int>& nums) {
    sort(nums.begin(), nums.end());
    
    int sum = 0;
    for (int i = 0; i < nums.size(); i += 2) {
      sum += min(nums[i], nums[i + 1]);
    }
    
    return sum;
  }
};

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